My group worked at Station 8 and we discovered that because the weight is pulling down on the ring, you do not take account for the gravitational force. There is the contact force of the weight on the ring, the tension force os the string on the rope, and the tension force of the spring on the rope. The spring pulls the ring with a force of 4.2 N and the string pulls the ring with a force of 1.5 N. The weight that is pulling the ring downwards pulls with a force of 5.3 N. When you add more weight to the ring you can see the tension forces increasing. The net force is equal to zero because when you add the forces you can make them a triangle.
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You can also tell the net force is 0 because the ring has a velocity of 0. Also, is there a way to make the two tension forces equal? We tried to do this, but it always seemed like either the spring or then string was supporting the weight more than the other.
Newton's 1st states that if an object's velocity is constant, the net force on that object must equal zero. Because the object is at rest, or the velocity is constantly zero, Fnet must equal zero. This is why that when adding the vectors from the free body diagram, the last vector ends up where you started. When you move the ring, the string exerts a greater force on the ring than the spring. When mass is added, the forces become greater because the weight exerts a greater force on the string, etc. So, they exert a greater force back. This is Newton's 3rd Law.
In order to find the tension force of the spring, my group had to first make a free body diagram. On the diagram we only had to forces of the string on the ring, and the mass on the ring labeled. Then, we had to add these two vectors by placing them head to tail, and tail to head. Once we did this we were able to draw the resultant vector. We found that the resultant vector was 1.7. The spring pulls on the rope with a force of 1.7 and the string pulls on the rope with a force of 4.2.
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